Question

Find the value of (1+tan2θ)(1- sinθ) (1+ sinθ).​

Answer 1

Answer:

Answer

(1+tan

2

θ)(1−sinθ)(1+sinθ)

=(sec

2

θ)(1−sin

2

θ)

=(sec

2

θ)(cos

2

θ)

=(sec

2

θ)(

sec

2

θ

1

)

=1

Answer 2

Answer:

1

Step-by-step explanation:

(1+tan^2 θ) =sec ^2θ

(1-sin θ)(1+sin θ) = (1-sin ^ 2θ)

so,

(sec^2 θ)(1-sin ^ 2 θ)

1/cos ^2 θ * cos ^ 2 θ = 1