Question

find the value of (1+tan²Q)cos²Q solution​

Answer 1

Answer:

1

Step-by-step explanation:

We know, 1+tan^2Q=Sec^2Q

And SecQ=1/CosQ

=>Sec^2Q=1/Cos^2Q

So Sec^2Q.Cos^2Q = Cos^2Q/Cos^2Q

=>1

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Answer 2

Answer:

1

Step-by-step explanation:

$( 1+ tan^2Q) cos^2Q = ? , \\ we know that (sec^2Q- tan^2Q = 1 => 1+tan^2Q = sec^2Q)\\therefore, (sec^2Q)* cos^2Q = \frac{1}{cos^2Q} *cos^2Q= 1 \\therefore,? = 1$

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