find the value of 10 joules on a system which has 10cm, 100g, and 30 sec as the fundamental units
Answers
Answered by
120
Energy = (1/2)mv2
so E is proportional to mv2
E = 10 J = 10 Kg (m/s)2
10 J = 10 Kg (m/s)2 = 10 x 1000 g x (100 cm /s)2
= 10 x 10 x (100g) x (10 x 10 cm / s)2
= 100 x (100g) x (10x30 x 10cm/30s)2
= 100 x (100g) x (300 x 10cm/30s)2
= 100 x (300)2 x (100g) (10cm/30s)2
= 9000000 x 100g (10 cm / 30s)2
= 9000000 new unit
so E is proportional to mv2
E = 10 J = 10 Kg (m/s)2
10 J = 10 Kg (m/s)2 = 10 x 1000 g x (100 cm /s)2
= 10 x 10 x (100g) x (10 x 10 cm / s)2
= 100 x (100g) x (10x30 x 10cm/30s)2
= 100 x (100g) x (300 x 10cm/30s)2
= 100 x (300)2 x (100g) (10cm/30s)2
= 9000000 x 100g (10 cm / 30s)2
= 9000000 new unit
Answered by
26
Explanation:
Energy =(1/2)mv^2.
So, E is proportional to mv^2.
E= 10J = 10 Kg(m/s)^2.
10 J = 10 Kg(m/s)^2 = 10×1000g =(100cm/s)^2.
=10×10×(100g)×(10×10cm/s)^2.
=100×(100g)×(10×30×10cm/30s)^2.
=9000000×100g(10cm/30s)^2.
=9000000 new units.
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