find the value of 10^log10 (¾)×5^log5 ¾ ×3^log
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Answer:
Slight correction, you are not after a solution but the value of an expression.
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]Using point 2 to rewrite your expression, we have:
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]Using point 2 to rewrite your expression, we have:[math][\log(1) - \log(2)] + [\log(2) - \log(3)] + ... + [\log(8) - \log(9)] + [\log(9) - \log(10)][/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]Using point 2 to rewrite your expression, we have:[math][\log(1) - \log(2)] + [\log(2) - \log(3)] + ... + [\log(8) - \log(9)] + [\log(9) - \log(10)][/math][math]= \log(1) - \log(10)[/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]Using point 2 to rewrite your expression, we have:[math][\log(1) - \log(2)] + [\log(2) - \log(3)] + ... + [\log(8) - \log(9)] + [\log(9) - \log(10)][/math][math]= \log(1) - \log(10)[/math]Using point 2, this simplifies to: [math]-\log(10)[/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]Using point 2 to rewrite your expression, we have:[math][\log(1) - \log(2)] + [\log(2) - \log(3)] + ... + [\log(8) - \log(9)] + [\log(9) - \log(10)][/math][math]= \log(1) - \log(10)[/math]Using point 2, this simplifies to: [math]-\log(10)[/math]The actual answer depends on what base logarithm you are using. I will assume that you are using common logs (aka decimal logs or base-10 logs), in which case, from point 3, the expression reduces to [math]-1[/math]
Slight correction, you are not after a solution but the value of an expression.To evaluate your expression, I just need to use three simple points about logarithms, namely:[math]\log(1) = 0[/math][math]\log (a/b) = \log(a) - \log(b)[/math][math]\log_n(n) = 1[/math]Using point 2 to rewrite your expression, we have:[math][\log(1) - \log(2)] + [\log(2) - \log(3)] + ... + [\log(8) - \log(9)] + [\log(9) - \log(10)][/math][math]= \log(1) - \log(10)[/math]Using point 2, this simplifies to: [math]-\log(10)[/math]The actual answer depends on what base logarithm you are using. I will assume that you are using common logs (aka decimal logs or base-10 logs), in which case, from point 3, the expression reduces to [math]-1[/math]Answer: -1