find the value of 100 joule in a system which has 10 cm, 100cm and 30 sec as fundamental units
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Energy = (1/2)mv^2
so E is proportional to mv^2
E = 10 J = 10 Kg (m/s)^2
10 J = 10 Kg (m/s)^2
= 10 x 1000 g x (100 cm /s) = 10 x 10 x (100g) x (10 x 10 cm /s)^2
= 100 x (100g) x (10 x 30 x 10 cm/30s)^2
= 100 x (100g) x (300 x 10cm/30s)^2
= 100 x (300)^2 x (100g) (10cm/30s)^2
= 9000000 x 100g (10 cm / 30s)^2
= 9000000 new unit
i hope it will help you
regards
so E is proportional to mv^2
E = 10 J = 10 Kg (m/s)^2
10 J = 10 Kg (m/s)^2
= 10 x 1000 g x (100 cm /s) = 10 x 10 x (100g) x (10 x 10 cm /s)^2
= 100 x (100g) x (10 x 30 x 10 cm/30s)^2
= 100 x (100g) x (300 x 10cm/30s)^2
= 100 x (300)^2 x (100g) (10cm/30s)^2
= 9000000 x 100g (10 cm / 30s)^2
= 9000000 new unit
i hope it will help you
regards
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