Question

find the value of 1000a^3+27b^6

Answer 1

Solution:

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Given:

$1000a^3 + 27b^6$


As we know,

=> $1000a^3 = (10a)^3$

=> $27b^6 = (3b^2)^3$

and

a³ + b³ = (a + b)(a² - ab + b²)

and hence,

=> $1000a^3 + 27b^6 = (10a + 3b^2)((10a)^2 - (10a)(3b^2) + (3b)^2)$

=> ∴ $1000a^3 + 27b^6 = (10a + 3b^2)(100a^2 - 30ab^2 +9b^4)$

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