Question

find the value of (101)2 by using suitable identity

Answer 1

it can be written as --- (100+1)^2
we know that (a+b)^2 =a^2+b^2+2ab
then
it is
100^2 + 1^2 + 2×1×100
= 10000 + 1+ 200
= 10201
hope it helps

Answer 2

Hi ,
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We know the algebraic identity.,

( x + y )² = x² + 2xy+ y²

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Now ,

( 101 )²

= ( 100 + 1 )²

= ( 100 )² + 2 × 100 × 1 + 1²

= 10000 + 200 + 1

= 10201

I hope this helps you.

: )