find the value of (106)cube - (94)cube using a suitable identity....
Answers
Answered by
11
Hey!!
106³-94³
=(106-94)(106²+106*94+94²)[a³-b³=(a-b)(a²+ab+b²)]
=12(11236+9964+8836)
=12*30036
=360432(Ans)
Hope it will help you☺☺
106³-94³
=(106-94)(106²+106*94+94²)[a³-b³=(a-b)(a²+ab+b²)]
=12(11236+9964+8836)
=12*30036
=360432(Ans)
Hope it will help you☺☺
keertana2004:
identity used here?in the form a,b,c.....
please reply....
a³-b³=(a-b)(a²+ab+b²)
thanks...
welcome
Answered by
7
Hey Mate! →→ (100+6)³ - (100-6)³
Expanding:
(a+b)³−(a−b)³
=(a³+3a²b+3ab²+b³)−(a³−3a²b+3ab²−b³)
=6a²b+2b²
=2b(3a²+b²)
Hence, 2b(3a²+b²) → 2×6(3×100²+6²)
→ 12(3×10000+36)
→ 12(30000+36)
→ 360000+432 = 360432
Expanding:
(a+b)³−(a−b)³
=(a³+3a²b+3ab²+b³)−(a³−3a²b+3ab²−b³)
=6a²b+2b²
=2b(3a²+b²)
Hence, 2b(3a²+b²) → 2×6(3×100²+6²)
→ 12(3×10000+36)
→ 12(30000+36)
→ 360000+432 = 360432
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