Find the value of 125 p³-8 q³ if 5p- 2q = 1 and pq = 2.
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p³-q³ =( p-q ) ×(p²+pq+q² )
125 p³-8 q³ = (5p-2q) (25p² + 10pq + 4q² )
= ( 1 ) {25 p²+ 4q² + 10 ( 2 )}
= 25 p² + 4q² + 20
= ( 5p )² + (-2q )² + 20
= ( 5p - 2q )² +20 pq + 20
= ( 1 ) ² + 20 ( 2 ) + 20
=1 + 40 + 20 = 61
hey mate I think the answer is 61
125 p³-8 q³ = (5p-2q) (25p² + 10pq + 4q² )
= ( 1 ) {25 p²+ 4q² + 10 ( 2 )}
= 25 p² + 4q² + 20
= ( 5p )² + (-2q )² + 20
= ( 5p - 2q )² +20 pq + 20
= ( 1 ) ² + 20 ( 2 ) + 20
=1 + 40 + 20 = 61
hey mate I think the answer is 61
shreya1723:
the ans is correct
isn't it
it is
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