Math, asked by atec7484, 11 months ago

Find the value of 125p^3-8q^3 if 5p-2q=1 and pq=2?

Answers

Answered by anupamsharma8051
0

Answer:

185436-₹5;₹57789964

Answered by Tiya8093722
2

If we assume p=1 and q=2

Then,

5p-2q=1

=> 5×1-2×2=1

=> 5-4=1

=> 1=1

125p³-8q³

= (5p)³-(2q)³

= (5p-2q){(5p)²+5p×2q+(2q)²}

= 1 × (25p²+10pq + 4q²)

= 25p²+4q²+10×2

= 25p²+4q²+20

= 25 ×1×1+4×2×2+20

= 25+16+20

= 61

Hope it helps you.....

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