Find the value of 125p^3-8q^3 if 5p-2q=1 and pq=2?
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0
Answer:
185436-₹5;₹57789964
Answered by
2
If we assume p=1 and q=2
Then,
5p-2q=1
=> 5×1-2×2=1
=> 5-4=1
=> 1=1
125p³-8q³
= (5p)³-(2q)³
= (5p-2q){(5p)²+5p×2q+(2q)²}
= 1 × (25p²+10pq + 4q²)
= 25p²+4q²+10×2
= 25p²+4q²+20
= 25 ×1×1+4×2×2+20
= 25+16+20
= 61
Hope it helps you.....
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