Question

find the value of: (13/21÷39/42)×(-3/5)​

Answer 1

Answer:

-0.4

Step-by-step explanation:

(13/21÷39/42)x(-3/5)

=13/21x42/13(x-1/5)

=1/21x42x(-1/5)

=14/7x(-1/5)

=2(-1/5)

=-2/5

=-0.4

Answer 2

Answer:

=> $\frac{-2}{5}$

Step-by-step explanation:

Given that:-

$[\frac{13}{21}\div\frac{39}{42}]\times [\frac{-3}{5}]$

To Find:- The value of the expression,

By using the method of BODMAS,

It is a method of performing various arithmetic operations to solve various expressions.

As we have,

=> $[\frac{13}{21}\div\frac{39}{42}]\times [\frac{-3}{5}]$

Invert the divisor and multiply it by the rational number inside the brackets, then by the rational number outside the brackets.

=> $[\frac{13}{21}\times \frac{42}{39}]\times [\frac{-3}{5}]$

Cancel out the common factors and then, multiply them.  

=> $[\frac{2}{3}]\times [\frac{-3}{5}]$

Multiply again, we get

=> $\frac{-6}{15}$

Now canceling the terms,

=> $\frac{-2}{5}$

Hence, the required solution is $\frac{-2}{5}$.