Question

find the value of 15 x^3 y^3 , when x=8 and y=7

Answer 1

Answer:

0

Step-by-step explanation:

(x-15)^3-(y-8)^3 where,x-y =7

=> {(x-15)-(y-8)} {(x-15)^2+(y-8)^2+(x-15)(y-8)}

We get the above from identity

a^3-b^3=(a-b){a^2+b^2+ab}

=> (x-15-y+8) {(x-15)^2+(y-8)^2+(x-15)(y-8)}

=> (7-7).... As,x-y=7

=0

So the ans. Is 0