find the value of 15 x^3 y^3 , when x=8 and y=7
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0
Answer:
0
Step-by-step explanation:
(x-15)^3-(y-8)^3 where,x-y =7
=> {(x-15)-(y-8)} {(x-15)^2+(y-8)^2+(x-15)(y-8)}
We get the above from identity
a^3-b^3=(a-b){a^2+b^2+ab}
=> (x-15-y+8) {(x-15)^2+(y-8)^2+(x-15)(y-8)}
=> (7-7).... As,x-y=7
=0
So the ans. Is 0
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