Physics, asked by arpit139010, 7 months ago

find the value of (16/81)-³/⁴​

Answers

Answered by IIMidnightHunterII
18

Answer:

 = ( \frac{16}{81} )^{ \frac{ - 3}{4} } \\  \\ =  ( \frac{ {2}^{4} }{ {3}^{4} }  ) ^{ \frac{ - 3}{4} }  \\  \\  =  \frac{ {2}^{4 \times  \frac{ - 3}{4} } }{ {3}^{4 \times  \frac{ - 3}{4} } }  \\  \\    = \frac{ {2}^{ - 3} }{ {3}^{ - 3} }  \\  \\  =  \frac{ {3}^{3} }{ {2}^{3} }  \\  \\  =  \frac{27}{8}

Answered by sarthshende5120
1

Answer:\frac{27}{8}

Explanation:

\frac{16}{81}^{-\frac{3}{4} }=\frac{81}{16}^{\frac{3}{4} }=(\sqrt[4]{\frac{81}{16} }})^{3}=(\frac{\sqrt[4]{81} }{\sqrt[4]{16} })^3=(\frac{3}{2} )^3=\frac{27}{8}

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