Question

Find the value of 16x +1/16 x, if 4x-1/4x=7​

Answer 1

(i) Let the required number be x.

So, five times the number will be 5x.

∴ 5x = 40

(ii) Let the required number be x.

So, when it is increased by 8, we get x + 8.

∴ x + 8 = 15

(iii) Let the required number be x.

So, when 25 exceeds the number, we get 25 - x.

∴ 25 - x = 7

(iv) Let the required number be x.

So, when the number exceeds 5, we get x - 5.

∴ x - 5 = 3

(v) Let the required number be x.

So, thrice the number will be 3x.

∴ 3x - 5 = 16

(vi) Let the required number be x.

So, 12 subtracted from the number will be x - 12.

∴ x - 12 = 24

(vii) Let the required number be x.

So, twice the number will be 2x.

∴ 19 - 2x = 11

(viii) Let the required number be x.

So, the number when divided by 8 will be

x

8

.

∴

x

8

= 7

(ix) Let the required number be x.

So, four times the number will be 4x.

∴ 4x - 3 = 17

(x) Let the required number be x.

So, 6 times the number will be 6x.

∴ 6x = x + 5

Answer 2

Step-by-step explanation:

$\huge\red{Answer}$

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4x+y=7 and 16x+ky=28

Comparing the above equation with the equation a

1

x+b

1

y=c

1

and

a

2

x+b

2

y=c

2

respectively.

a

1

=4,b

1

=1,c

1

=7,

a

2

=16,b

2

=k,c

2

=28

a

2

a

1

=

16

4

=

4

1

,

b

2

b

1

=

k

1

and

c

2

c

1

=

4

1

∴ The condition for the simultaneous equations to have infinitely many solutions is.

a

2

a

1

=

b

2

b

1

=

c

2

c

1

∴

4

1

=

k

1

=

4

1

∴

4

1

=

k

1

∴k=4.

Hence the simultaneous equations 4x+y=7 and 16x+ky=28 will have infinitely many solutions for k=4.

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