Question

find the value of 16x^2+56xy+49y^2, when x =2, y=-1.​

Answer 1

Answer:

1

Step-by-step explanation:

given x =2 and y =-1

we have to simply put the values in the equation

$16x^2 +56xy +49y^2 \\16 * 2^{2} + 56 *2*(-1) +49 (-1)^2\\64 -112+49\\113 -112\\1$

Hence the answer is 1

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