find the value of 16xy,4xy,6xy,????
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8
Given points are A(6, 1), B(1, 3) and C(x, 8). We need to find the value of x such that AB = BC.
We know that the distance between the points (x1, y1) and (x2, y2) is
⇒ AB = BC
⇒ AB2 = BC2
⇒ (6 - 1)2 + (1 - 3)2 = (1 - x)2 + (3 - 8)2
⇒ (5)2 + (- 2)2 = (1 - x)2 + (- 5)2
⇒ 25 + 4 = 1 - 2x + x2 + 25
⇒ x2 - 2x - 3 = 0
⇒ x2 - 3x + x - 3 = 0
⇒ x(x - 3) + 1(x - 3) = 0
⇒ (x + 1)(x - 3) = 0
⇒ x + 1 = 0 (or) x - 3 = 0
⇒ x = - 1 (or) x = 3
∴ The values of x are - 1 or 3.
Answered by
2
Step-by-step explanation:
x+y=√3 ____i
x-y=√2_____ii
Square (i) & (ii)
x²+y²+2xy=3 __iii , x²+y²-2xy=2 ___iv
Adding above eqs.
2{x²+y²}=5
Subtracting (iii) - (iv)
4xy=1
16xy(x²+y²) can be written as 2*(4xy)*(2(x²+y²))
16xy(x²+y²) = 10.
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