Math, asked by neela1, 1 year ago

find the value of 1by4by2and7 + 1by3by11and13 + 1by5by9


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neela1: find the value of this question

Answers

Answered by DarkUnix
1
I'm not sure, but it must be what I'm thinking.
In mathematics 'by' usually mean multiplication
So we can write it as 2(1*4) + 7(1*4) + 11(1*3) + 13(1*3) + 1*5*9
And then we do the simple addition and multiplication,
= 8 + 28 + 33 + 39 + 45
= 153

neela1: why this question will multiply
neela1: what is the reason
neela1: its a mixed fraction
DarkUnix: 'by' in mathematics mean multiplication, 1/2 by 4 by 2 for example on solving, will get 4
neela1: wait
neela1: first check on the google and then tell me
DarkUnix: what is the answer anyways?
neela1: you tell me
DarkUnix: I told you already, according to me 153
neela1: kkkkk
Answered by Shivendra2489
0
nt sure but i think its 11758\5460


Shivendra2489: by means divide here
neela1: what are you talking you don't no so plzz keep quite
Shivendra2489: thank you for so much of respect
neela1: shut up
neela1: do your own work
neela1: i am not giving you any kind of respect
Shivendra2489: i really dont need from you.....i think you need to first shut up,,,,,,,,
neela1: you shut upa nd get lost
neela1: i hadn't ask any question
neela1: so plz do your own work
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