find the value of 1by4by2and7 + 1by3by11and13 + 1by5by9
neela1:
tell me the answer
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Answered by
1
I'm not sure, but it must be what I'm thinking.
In mathematics 'by' usually mean multiplication
So we can write it as 2(1*4) + 7(1*4) + 11(1*3) + 13(1*3) + 1*5*9
And then we do the simple addition and multiplication,
= 8 + 28 + 33 + 39 + 45
= 153
In mathematics 'by' usually mean multiplication
So we can write it as 2(1*4) + 7(1*4) + 11(1*3) + 13(1*3) + 1*5*9
And then we do the simple addition and multiplication,
= 8 + 28 + 33 + 39 + 45
= 153
Answered by
0
nt sure but i think its 11758\5460
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