find the value of (2^0+3^0+4^0)-1
pls tell the answer
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Answered by
1
Answer:
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Step-by-step explanation:
2
Answered by
1
Answer:
2
Step-by-step explanation:
As we know that x^0 = 1
so (2^0+3^0+4^0)-1 = (1+1+1)-1
= 3-1
= 2
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