find the value of (2^0+3^-1)×3^2
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- (2^0+3^-1)×3^2
- (1 + 1/3) × 9
- 3 + 1/3 × 9
- 4/3 × 9
- 4 × 3
- 12
Hence,
- the value of (2^0+3^-1)×3^2 is 12
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