find the value of (2-¹×2-²)%2-³
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bhailalbhoi4:
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which class you are?
I'm class:6th
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Answer:
a²-b²+2bc-c² =a² - (b² -2bc +c²)
=a² - (b-c)²
=(a-(b-c))(a+(b-c))
[ using identity a²-b² =(a-b)(a+b) ]
= (a-b+c)(a+b-c)
hence.,a²-b²+2bc - c² = (a-b+c)(a+b-c)
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