Question

find the value of (2^-1×4^-1)÷2^-2​

Answer 1

Step-by-step explanation:

=(1/2 ×1/4) ÷1/4

=(1/8)÷1/4

=1/8×4

=1/2=2 -1

Answer 2

The value of $\bf ({2}^{ - 1} \times {4}^{ - 1} ) \div ( {2}^{ - 2} )$ is 1/2.

Given:

• A mathematical expression.
• $({2}^{ - 1} \times {4}^{ - 1} ) \div ( {2}^{ - 2} )$

To find:

• Find the value of expression.

Solution:

Formula to be used:

$\bf {a}^{ - n} = \frac{1}{ {a}^{n} }$

Step 1:

Simplify the expression.

$({2}^{ - 1} \times {4}^{ - 1} ) \div ( {2}^{ - 2} ) = \left ( \frac{1}{2} \times \frac{1}{4} \right ) \div \frac{1}{ {2}^{2} }$

Step 2:

Solve the expression.

$\left ( \frac{1}{2} \times \frac{1}{4} \right ) \div \frac{1}{ {2}^{2} } = \frac{1}{8} \times \frac{4}{1}$

cancel common factors of numerators and denominators

$\left ( \frac{1}{2} \times \frac{1}{4} \right ) \div \frac{1}{ {2}^{2} } = \frac{1}{2}$

Thus,

Value of $\bf({2}^{ - 1} \times {4}^{ - 1} ) \div ( {2}^{ - 2} )$ is $\bf {2}^{ - 1}$ or 1/2.

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