Question

find the value of (2^-1 - 4^-1)^2
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Answer 1

Answer:

2² is correct solution

Step-by-step explanation:

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Answer 2

$( {2}^{ - 1} - {4}^{ - 1} )^{2} \\ = (\frac{1}{2} - \frac{1}{4} )^{2} \\ (LCM \: of \: 2 \: and \: 4 \: is \: 4) \\ = ( \frac{(1 \times 2) - 1}{4} ) ^{2} \\ = {( \frac{2 - 1}{4}) }^{2} \\ = {( \frac{1}{4} )}^{2} \\ = \frac{1}{4} \times \frac{1}{4} \\ = \frac{1}{16} \\ = {16}^{ - 1} = {4}^{ - 2} = {2}^{ - 4}$

Last three numbers are answers.

hope it helps.