Question

find the value of 2*1!+4*2!+6*3!+...+(2n)*n!

Answer 1

Answer:

Correct option is D)

i

2

+ i

4

+ i

6

+ ...upto (2n+1) terms

=(−1+1)+(−1+1)+(−1+ .....upto (2n+1))terms ⇒ (odd terms)

=0+0+....−1

=−1

Hence, option D is correct.

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