Question

find the value of √2√2√2√2√2

Answer 1

$<b>$Answer :

$= > \sqrt{2} \sqrt{2} \sqrt{2 } \sqrt{2} \sqrt{2} \\ \\ = > \sqrt{2 } \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} \\ \\ = > \sqrt{2 \times 2 \times 2 \times 2 \times 2} \\ \\ pairing \: them \\ \\ = > \sqrt{(2 \times 2)(2 \times 2)(2)} \\ \\ = > 2 \times 2 \sqrt{(2)} \\ \\ = > 2 \times 2 \sqrt{2} \\ \\ = >4 \sqrt{2} \\ \\ value \: of \: \sqrt{2} = 1.41 \\ \\ = > 4 \times 1.41 \\ \\ = > 5.64$

$\color{blue}\underline\textbf{Hence, your required answer is 5.64!!}$

Tysm for the question :)

Answer 2

hello mate

Sri here

$\sqrt{2 \times 2 \times 2 \times 2 \times 2} \\ = 2 \times 2 \times \sqrt{2} \\ = 4 \sqrt{2} \\ =4 \times 1.414 \\ = 5.656$

I hope it is answer