Question

Find the value of :
2√2 cos 45°.cos60° + 2√3 sin 60° tan 60° – cos0°

Answer 1

Answer:

$3 \sqrt{3} - 1$

Explanation:

solved in attachment

Answer 2

2√2 cos 45°.cos60° + 2√3 sin 60° tan 60° – cos0° = 3√3

Explanation:

cos 0° = 1

cos 45° = 1/√2

cos 60° = 1/2

sin 60° = √3/2

tan 60° = √3

Substituting the values, we get:

2√2 cos 45°.cos60° + 2√3 sin 60° tan 60° – cos0°

 = 2√2 *(1/ √2) * (1/ 2) + 2√3 *(√3/ 2) * √3 – 1

= (2 * 1 * 1/2 ) + (3*√3 ) - 1

= 1 + 3√3 - 1

= 3√3