Math, asked by dfgsdgg, 1 year ago

Find the value of [(-2/3)^2]^2

Answers

Answered by thameshwarp9oqwi
35

Answer:

==> ((-2/3)²)²)

===> (-2/3)^4

==>  16/243

Answered by amitnrw
13

[(-2/3)²]² = 16/81

Given:

  • [(-2/3)²]²

To Find:

  • Value

Solution:

  • a² = a x a
  • a² = (-a)²
  • (a/b)² = a²/b²

[(-2/3)²]²

Step 1:

Use a² = (-a)²  hence,

= [( 2/3)²]²

Step 2:

Use (a/b)² = a²/b²  hence,

= [ 2²/3²]²

Step 3:

Use a² = a x a  hence 2² = 2 x  2 = 4  and 3² = 3 x 3 = 9

= [ 4/9]²

Step 4:

Use (a/b)² = a²/b²  hence,

=  4²/9²

Step 5:

Use a² = a x a  hence 4² =  4 x  4 = 16  and 9² = 9 x 9 = 81

= 16/81

Hence, [(-2/3)²]² = 16/81

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