Question

find the value of: ((2÷3)²)³ × (1÷3)‐⁴×3‐¹×6‐¹​

Answer 1

Step-by-step explanation:

$((2 \div 3)^{2} )^{3} \times (1 \div 3)^{ - 4} \times {3}^{ - 1} \times {6}^{ - 1} \\ = (( \frac{2}{3} )^{2} )^{3} \times ( { \frac{1}{3} })^{ - 4} \times \frac{1}{3} \times \frac{1}{6} \\ = ({ \frac{4}{9} })^{3} \times 3 \times \frac{1}{18} \\ = \frac{64}{729} \times \frac{1}{6} \\ = \frac{32}{2187}$