Question

Find the value of [ 2 -3(2-3)^3]^3​

Answer 1

Appropriate Question -

• Find the value of [2 - 3 (2 - 3)³]³.

Answer -

• The required number is 125.

To find -

• The value of [2 - 3 (2 - 3)³]³.

Step-by-step explanation -

$\bf \implies[2 - 3 \: (2 - 3)^{3} ]^{3}$

$\bf \implies[2 - 3 \: ( - 1)^{3}]^{3}$

$\bf \implies [2 - 3 \: ( - 1)]^{3}$

$\bf\implies [2 - 3 \times ( - 1)] ^{3}$

$\bf \implies [2 + 3]^{3}$

$\bf\implies [5]^{3}$

$\implies \bf125$

Hence -

• The answer is 125.

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Know more -

The rule used to solve the above problem is known as BODMAS.

BODMAS stands for -

• B = Bracket
• O = Of
• D = Division
• M = Multiplication
• A = Addition
• S = Subtraction

Order of Brackets -

• () = Round brackets or first brackets.
• {} = Curly brackets or second brackets.
• [] = Square brackets or third brackets.

It means that -

• To solve a sum using the BODMAS rule, we first have to solve the round brackets, then the curly brackets and at last, the square brackets. Then we can solve the remaining sum according to ODMAS.

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Answer 2

To find :

the value of [2-3(2-3)³]³

Solution :

[2-3(2-3)³]³

= [2-3(-1)³]³

= [2-3(-1)]³

= [2+3]³

= 125

so, [2-3(2-3)³]³= 125