Math, asked by sarojv1130, 8 months ago

find the value of 2^3+4^3+6^3.....…...to 20 terms​

Answers

Answered by sathyamargerate0410
0

Answer:

3,52,800

Step-by-step explanation:

2³+4³+6³+8³.........n terms

2³(1³+2³+3³+4³+...... nterms)

[n²(n+1)²]

4

8[n²(n+1)²]

4

2n²(n+1)²

Here n=20

So 2n²(n+1)²=2(20)²(21)²

=3,52,800

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