Math, asked by aleeva634, 7 hours ago

find the value of [2/3 x - 3/2 y}^2

Answers

Answered by dineshseethalam04
0

Answer:

[2/3 x - 3/2 y]²

(2/3 x) ² + (3/2 y)² - 2*2/3*3/2

4/9 x² + 9/4 y² - 2*6/6

4/9 x² + 9/4 y² - 2*1

hence the answer is

4/9 + 9/4 -2

Similar questions