find the value of 2^30+2^29+2^28/2^31+^30-2^29
Answers
Answered by
8
(2^30 + 2^29 + 2^28)/(2^31 + 2^30 - 2^29)
= (2^(28+2) + 2^(28+1) + 2^28)(2^(29+2) + 2^(29+1) - 2^29)
= (2^28.2^2 + 2^28.2 + 2^28)/(2^29.2^2 + 2^29.2 - 2^29)
= 2^28( 2^2 + 2 + 1)/2^29(2^2 + 2 -1 )
= 2^28(4 + 3)/2^29(4 +1 )
= 7/10
= (2^(28+2) + 2^(28+1) + 2^28)(2^(29+2) + 2^(29+1) - 2^29)
= (2^28.2^2 + 2^28.2 + 2^28)/(2^29.2^2 + 2^29.2 - 2^29)
= 2^28( 2^2 + 2 + 1)/2^29(2^2 + 2 -1 )
= 2^28(4 + 3)/2^29(4 +1 )
= 7/10
Similar questions