Question

find the value of 2^(4+log3base2)​

Answer 1

Answer:

y=6+log

3/2

⎝

⎛

3

2

1

4−

3

2

1

4−

3

2

1

⎠

⎞

Let x=

3

2

1

4−

3

2

1

4−

3

2

1

−−−

=x

⇒x=

3

2

1

4−x

⇒x=

3

2

1

4−x

⇒3

2

x=

4−x

⇒(3

2

x)

2

=4−x

⇒18x

2

+x−4=0

⇒18x

2

+9x−8x−4=0

⇒9x(2x+1)−4(2x+1)=0

⇒(9x−4)(2x+1)=0

⇒x=−

2

1

or x=

9

4

but x=

3

2

1

4−

3

2

1

can not be negative

⇒x=

9

4

⇒y=6+log

3/2

(x)=6+log

3/2

(

9

4

)

=6+log

3/2

(3/2)

−2

=6+(−2)(log

3/2

3/2)

=6−2(1)=6−2

=4