Math, asked by nithika45, 11 months ago

find the value of (2^5)^11×(2^15)^4-(2^5)^18×(2^5)^5

Answers

Answered by rajeev378
10
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Here is your answer

( {2}^{5} ) {}^{11}  \times ( {2}^{15} )4 - ( {2}^{5} ) {}^{18}  \times  ({2}^{5} ) {}^{5}  \\  =  {2}^{5 \times 11}  \times  {2}^{15 \times 4}  -  {2}^{5 \times 18}  \times  {2}^{5 \times 5}  \\  =  {2}^{55}  \times  {2}^{60}  -  {2}^{90}  \times  {2}^{25}  \\  =  {2}^{55 + 60}  -  {2}^{90 + 25}  \\  =  {2}^{115}  -  {2}^{115}  \\  = 0

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Answered by MonarkSinghD
8
Hi friends

Here is your answer

( {2}^{5} ) {}^{11} \times ( {2}^{15} )^4 - ( {2}^{5} ) {}^{18} \times ({2}^{5} ) {}^{5} \\ <br /><br />= {2}^{5 \times 11} \times {2}^{15 \times 4} - {2}^{5 \times 18} \times {2}^{5 \times 5} \\ = {2}^{55} \times {2}^{60} - {2}^{90} \times {2}^{25} \\ = {2}^{55 + 60} - {2}^{90 + 25} \\ = {2}^{115} - {2}^{115} \\ = 0

Hope it helps you

@ MSD
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