find the value of: (2+6yz)(x²y²+2yz)
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Answered by
2
6x²y³z+2x²y²+12y²z²+4yz
Step-by-step explanation:
(2+6yz)(x²y²+2yz)
=(2+6yz)(x²y²+2yz)
=(2)(x²y²)+(2)(2yz)+(6yz)(x²y²)+(6yz)(2yz)
=2x²y²+4yz+6x²y³z+12y²z²
=6x²y³z+2x²y²+12y²z²+4yz
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Answered by
0
Answer:
2x2y2 + 4yz + 6x2y3z + 12y2z2
Step-by-step explanation:
(2+6yz)(x²y²+2yz)
=2*x2y2 + 2*2yz + 6yz*x2y2 + 6yz*2yz
=2x2y2 + 4yz + 6x2y3z + 12y2z2
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