Math, asked by NyashaShriv, 1 month ago

find the value of (2π+7y) (2π-7y)​

Answers

Answered by Usernamesarelame
0

Answer:

39.4384 - 49y^2

Step-by-step explanation:

(2π+7y) (2π-7y)​

= 4π^2 - 49y^2

= 4 *3.14*3.14 - 49y^2

= 39.4384 - 49y^2

I used a^2 - b^2 formula [a^2 - b^2 = (a+b)(a-b)]

Answered by galimanishkumar
0

88/49-49y^2 is the answer

Step-by-step explanation:

(2pi+7y)(2pi-7y)

=4pi^2-49y^2

=4(22/7)^2-49y^2

=4(44/49)-49y^2

=88/49-49y^2

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