find the value of (2π+7y) (2π-7y)
Answers
Answered by
0
Answer:
39.4384 - 49y^2
Step-by-step explanation:
(2π+7y) (2π-7y)
= 4π^2 - 49y^2
= 4 *3.14*3.14 - 49y^2
= 39.4384 - 49y^2
I used a^2 - b^2 formula [a^2 - b^2 = (a+b)(a-b)]
Answered by
0
88/49-49y^2 is the answer
Step-by-step explanation:
(2pi+7y)(2pi-7y)
=4pi^2-49y^2
=4(22/7)^2-49y^2
=4(44/49)-49y^2
=88/49-49y^2
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