Find the value of (2^a/2^b)^a+b.(2^b/2^c)^c+b.(2^c/2^a)^a+c
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Answer:
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Step-by-step explanation:
a
2
+b
2
+c
2
=2(a+2b−2c)−9
a
2
−2a+b
2
−4b+c
2
+4c+9=0
a
2
−2(a)(1)+(1)
2
+b
2
−2(b)(2)+(2)
2
+c
2
+2(c)(2)+(2)
2
=0
(a−1)
2
+(b−2)
2
+(c+2)
2
=0
⟹a=1,b=2,c=−2
a+b+c=1+2−2=1
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