Question

find the value of (2-a)³+(2-b)³+(2-c)³-3(2-a)(2-b)(2-c) when a+b+c=6

Answer 1

if x + y +z =0 then x(cube)+y(cube)+z(cube)-3xyz=0

therefore, if x = 2-a ; y = 2-b ; z = 2-c

then x+y+z i.e., 2-a+2-b+2-c=0.this implies that a+b+c=6

then x(cube)+y(cube)+z(cube)-3xyz=0 i.e,

(2-a)3+(2-b)3+(2-c)3-3(2- a)(2-b)(2-c) = 0


i hope u understood

Answer 2

ANSWER:

Therefore, (2-a)³+(2-b)³+(2-c)³-3(2-a)(2-b)(2-c) = 0

Hope It Will Help You..!!