Find the value of
2 cos x - cos 3x- cos 5x =
Answers
Answered by
1
Answer:
f(x)=2cosx−cos3x−cos5x
=2cosx−(2cos4xcosx)
=2cosx(1−cos4x)
=2cosx[cos
2
2x+sin
2
2x−(cos
2
2x−sin
2
2x)]
=2cosx×2sin
2
2x[cos2x=cos
2
x−sin
2
x]
=4cosxsin
2
2x
=4cosx(2sinxcosx)
2
⇒f(x)=16sin
2
xcos
3
x
Answered by
0
Answer:
2cos x - cos3x - cos5x = 16 sin^2 x cos ^3 x
Attachments:
Similar questions