Question

find the value of :-
2(cos²45°+tan²60°) -6(sin²45°-tan²30°)​

Answer 1

HOPE YOU UNDERSTOOD THE SOLUTION

Answer 2

Step-by-step explanation:

$2( \frac{1}{ \sqrt{2} } {}^{2} + \sqrt{3} {}^{2} ) - 6( \frac{1}{ \sqrt{2}} {}^{2} - \frac{1}{ \sqrt{3} } {}^{2} )$

$= 2( \frac{1}{2} + 3) - 6( \frac{1}{2} - \frac{1}{3} ) \\ = 2( \frac{7}{2} ) - 6( \frac{1}{6} ) \\ = 7 - 1 \\ = 6$

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