find the value of 2 log 3 + 3 log 10
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Step-by-step explanation:
For a simple pendulum, force constant or spring factor k is proportional to mass m, therefore, m cancels out in denominator as well as in numerator. That is why the time period of simple pendulum is independent of the mass of the bob.
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Answer:
2log5+log3+3log2−1/2log36−2log10
Let us simplify the expression,
=2log5+log3+3log2−1/2log62−2log(10)
=2log5+log3+3log2−1/2×2log6−2×(1)
=2log5+log3+3log2−log(3×2)−2
=2log5+log3+3log2−(log3+log2)−2
=2log5+log3+3log2−log3−log2−2
=2log5+2log2−2
=2×(log5+log2)−2
=2×log(5×2)−2
=2log10−2
=2(1)−2
=0
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