Math, asked by Arpitsaxena07, 19 days ago

Find the value of: 2 sin²30°-3cos²45°+tan²60°​

Answers

Answered by paramcomforchowdhury
0

Answer:

2 sin²30°-3cos²45°+tan²60°

= 2(sin30°)²-3(cos45°)²+(tan60°)²

= 2(1/2)²-3(1/√2)²+(√3)²

= 2(1/4)-3(1/2)+(3)

=(1/2)-(3/2)+(3)

=(1-3+6)/2

=4/2

=2

Answered by devindersaroha43
5

Answer:

Step-by-step explanation:

it's answer will be 2 after simplyfying identities

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