Math, asked by Dhemanshu2690, 1 year ago

find the value of √2 sin45+√3tan30-1/2sec60

Answers

Answered by mysticd
2

Answer:

1

Explanation:

********************

i) sin45° = 1/√2

ii) tan30° = 1/√3

iii ) sec60 = 2/1

********************

Now ,

The value of √2 sin45+√3tan30-1/2sec60

= √2(1/√2)+√3(1/√3)-(1/2)×2

= 1 + 1 - 1

= 1

••••

Answered by gugulothhemanth9
0

Answer:

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