Math, asked by khadijanisar892, 14 hours ago

Find the value of√2 up to two decimal place square root

Answers

Answered by aminasafna15
0

Answer:

1.414 is the value of √2.

Answered by mathdude500
4

\large\underline{\sf{Solution-}}

\rm \:  \sqrt{2}  \\

So, by using Long Division Method, we have

\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\:1.41\:\:}}}\\ {\underline{\sf{1}}}& {\sf{\:\:2.0000 \:\:}} \\{\sf{}}& \underline{\sf{ 1 \:  \:  \:  \:  \:  \:  \:  \: }} \\ {\underline{\sf{24}}}& {\sf{ 100 \:  \:  \:  \:  }} \\{\sf{}}& \underline{\sf{ 96  \:  \: }} \\ {\underline{\sf{281}}}& {\sf{\:\: \:  \: 400}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \: 281}} \\ {\underline{\sf{}}}& {\sf{ \:  \:  \:  \:  \: 119}} {\sf{}}&{\sf{\:\:\:\:}}\end{array}\end{gathered} \\

So,

\rm\implies \:\boxed{ \bf{ \: \sqrt{2} = 1.41 \:  \: }} \\

\rule{190pt}{2pt}

Additional Information :-

Let's solve few example.

Question :- Find the value of√2 up to three decimal place.

So, by using Long Division Method, we have

\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\:1.414 \:\:}}}\\ {\underline{\sf{1}}}& {\sf{\:\:2.000000 \:\:}} \\{\sf{}}& \underline{\sf{\:\: \: \: \: \: \: \: \:  \: 1 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{24}}}& {\sf{\:\: \: \: \: \:  \:  \: 100 \:  \:  \:  \:   \:  \:  \:  \:\:}} \\{\sf{}}& \underline{\sf{\:\: \: \: \: 96  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{281}}}& {\sf{\:\:400  \:\:}} \\{\sf{}}& \underline{\sf{\:\:281\:\:}} \\ {\underline{\sf{2824}}}& {\sf{\:\: \:  \: \:  \:  \:  11900\:\:}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \:  \:    \: 11296\:\:}} \\ {\underline{\sf{}}}& {\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \: \: 604\:\:}}{\sf{}}&{\sf{\:\:\:\:}}\end{array}\end{gathered}

Let's solve one more problem.

Question :- Find the value of√3 up to three decimal place.

So, by using Long Division Method, we have

\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\:1.732 \:\:}}}\\ {\underline{\sf{1}}}& {\sf{\:\:3.000000 \:\:}} \\{\sf{}}& \underline{\sf{\:\: \: \: \: \: \: \: \: \: 1 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{27}}}& {\sf{\:\: \: \: \: \: 200  \:  \:  \:   \:  \:  \:  \:\:}} \\{\sf{}}& \underline{\sf{\:\: 189   \:  \:  \:  \: \:\:}} \\ {\underline{\sf{343}}}& {\sf{\:\:1100  \:\:}} \\{\sf{}}& \underline{\sf{\:\:1029\:\:}} \\ {\underline{\sf{3462}}}& {\sf{\:\: \:  \: \:  \:  \:  7100\:\:}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \:  \:    \: 6924\:\:}} \\ {\underline{\sf{}}}& {\sf{\: \:  \:  \:  \:  \:  \:   \:  \: 176\:\:}}{\sf{}}&{\sf{\:\:\:\:}}\end{array}\end{gathered} \\

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