Find the value of 2^(x^2+x)=64
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if 2^(x^2+x)=64
2^(x^2+x)=2^6
x^2+x=6 (2=2)
x^2+x-6=0
x^2+3x-2x-6=0
x (x+3)-2 (x+3)=0
(x+3)(x-2)=0
if (x+3)=0
x=-3
if (x-2)=0
x=2
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