Math, asked by parneetkhunzan, 2 months ago

find the value of (2°+3-¹)×3²​

Answers

Answered by manupatankar
0

Step-by-step explanation:

(2°+3-¹)×3²

2° = 1 { a°=1}

3-¹ = 1/3 { n-¹ = 1/n and vice versa )

3²= 9

(2°+3-¹)×3²

(1+1/3)9

9/3

3 is the answer

Answered by unknownbeing143
2

Answer:

(2⁰+3^-1)3²

(1+3^-1)3²

1+3^-1×2

1+3^-2

1/1+1/9

9+1/9

10/9=> ans

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