find the value of (20)³-(30)³+(23)³ by indentity
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1
We know that,
If (a+b+c)=0, then a
3
+b
3
+c
3
=3abc
Here, 28+(−15)+(−13)=0
∴(28)
3
+(−15)
3
+(−13)
3
=3(28)(−15)(−13)=16380
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