find the value of : 20+(_30)
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Answer:
Ah, 20 + 30?
Well, let’s see…
20+30=30+20=10(2)+10(3)
10(2)= 5*2*2 and 10(3)= 3*5*2
5*2*2 + 3*5*2= 5* 2^2 + 3*5*2
Okay, now let 5=y, 2=x, and 3= z.
yx^2 + zyx
xy(x+z)
Now substitute the variables
2*5(2+3)
10(2+3)
=10(5)
=5*2(5)
=2(5^2)
=2(25)
=2(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1)
= 50(1^42) +10–5+(-5)
Simple
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