find the value of 2002*2002-1998*1998/4,000
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Answered by
2
Answer:
Let
S=22001+2199922000+21998
S=22000+1+21998+122000+21998
Using xm+n=xm⋅xn
S=22000⋅21+21998⋅2122000+21998
S=2(22000+21998)22000+21998
S=2\cancel(22000+21998)\cancel22000+21998
S=2
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Answered by
6
Answer:
we can write it as
4000 4000 cancelled
so ans is 4
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