Question

Find the value of(2020)³-(1001)³-(1019)³-3×2020×1001×1019​

Answer 1

Answer:

(1001)

3

=(1000+1)

3

Suitable identities is (x+y)

3

=x

3

+3x

2

y+3xy

2

+y

3

∴(1000+1)

3

=(1000)

3

+3(1000)

2

(1)+3(1000)(1)

2

+(1)

3

=1000000000+3000000+3000+1=1003003001