Question

find the value of............................​

Answer 1

Step-by-step explanation:

$\frac{ {2}^{36} }{ {2}^{34} } + \frac{ {3}^{28} }{ {3}^{27} } + \frac{ {5}^{37} }{ {5}^{35} } = {2}^{36 - 34} + {3}^{28 - 27} + {5}^{37 - 35}$

= 2² + 3 + 5²

= 4 + 3 + 25

= 32

Answer 2

Answer:-

To Find: Value of $\tt{\frac{{2}^{36}}{{2}^{34}} + \frac{{3}^{28}}{{3}^{27}} + \frac{{5}^{37}}{{5}^{35}}}$.

Exponent rule to be used:

$\boxed{{\frac{{x}^{a}}{{x}^{b}} = {x}^{a - b}}}$

So,

$\tt{\frac{{2}^{36}}{{2}^{34}} + \frac{{3}^{28}}{{3}^{27}} + \frac{{5}^{37}}{{5}^{35}}}$

$\tt{= {2}^{36 - 34} + {3}^{28 - 27} + {5}^{37 - 35}}$

$\tt{= {2}^{2} + {3}^{1} + {5}^{2}}$

$\tt{= 4 + 3 + 25}$

$\tt{= 7 + 25}$

$\tt{= 32}$

∴ $\bf{\frac{{2}^{36}}{{2}^{34}} + \frac{{3}^{28}}{{3}^{27}} + \frac{{5}^{37}}{{5}^{35}} = 32.}$